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I started going down a staircase. Having gone down 4 steps I saw X coming up. For one step that I take X goes up by two steps. I met X on the way going down. When I still had 7 steps to go down, X had gone up. Find the number of steps in the staircase.


Let total number of steps be n. When X started coming up, i had covered 4 steps already and when X has reached top, i still had 7 steps to go.

In the same time, X has covered n steps and i have covered n-11 steps. If speed of X is twice that of mine, n = 2(n-11)

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